Applying DeMorgan's Law
DeMorgan's Law
DeMorgan's Law applies in situations when a not (!) operator is being used in combination with either the and (&&) or the or (||) operators.
Truth Table to Prove DeMorgan's Law
| Rule |
Description |
Example
|
!(value1 && value2) |
evaluates to !value1 || !value2 where value1 and value2 are boolean expressions. |
!((5 > 7) && (3 !=0)) is equivalent to (5 <= 7) || (3 == 0) |
!(value1 || value2) |
evaluates to !value1 && !value2 where value1 and value2 are boolean expressions. |
!((val + 5 <= 0) || (5 == 5)) is equivalent to (val + 5 > 0) && (5 != 5) |
Resources
Practice: Using Logic Operators
Next Learn Tutorial
Learn: Comparing Objects with the Equals Method